Review: Fantastic book - 'Electric Eden'

Subject: Review: Fantastic book - 'Electric Eden'
From: JennyD
Date: 03 Jun 11 - 10:03 AM

I am currently reading "Electric Eden: Unearthing Britain's Visionary Music" by Rob Young. It's brilliantly well-written, a very compelling read, and covers the roots of the folk revival in the late 19th century and early 20th century and its connection to the folk-rock music of the 60s and 70s and its descendants today. He takes a close look at familiar artists like Fairport Convention, Steeleye Span, Pentangle, Nick Drake and so on, but also talks about people who were less familiar (to me at any rate), like Vashti Bunyan. I have just spent a very happy hour on YouTube looking up her music and Amazon will undoubtedly be even better off as a result of that. This is one of the few books where I've sat with a notebook in hand while reading it, to remind me to look up various things on the net.

Highly recommended for Mudcatters.

Subject: RE: Review: Fantastic book - 'Electric Eden'
From: GUEST,Lindy
Date: 08 Jun 11 - 12:57 AM

I just read an interesting review of this book by Rob Young in today's edition of the Los Angeles Times(Scott Timberg).

An 'Electric Eden' of British folk rock in the Los Angeles Times June 7, 2011.
[e-mail]

I really want to read this book now!

Subject: RE: Review: Fantastic book - 'Electric Eden'
From: Desert Dancer
Date: 08 Jun 11 - 02:28 AM

The current (though not the first) thread is here: Review: 'Electric Eden' by Rob Young. Linked to that is an earlier thread with discussion from then the book first came out (it's just come out in paperback).

~ Becky in Tucson

Subject: RE: Review: Fantastic book - 'Electric Eden'
From: Desert Dancer
Date: 08 Jun 11 - 02:30 AM

(The first thread also happens to currently be up on the thread list...)

Subject: RE: Review: Fantastic book - 'Electric Eden'
From: GUEST,Lindy
Date: 08 Jun 11 - 02:22 PM

Just wondering if anyone knows if this book will at some point be published in hardback? Or ONLY published in paperback?
Thanks.