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BS: Math problems
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Subject: RE: BS: Math problems From: gnu Date: 08 May 12 - 08:01 PM Hahahahaha... good one, Terry! |
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Subject: RE: BS: Math problems From: Leadfingers Date: 08 May 12 - 07:15 PM Ten Squared |
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Subject: RE: BS: Math problems From: gnu Date: 08 May 12 - 04:13 PM The Farside. |
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Subject: RE: BS: Math problems From: gnu Date: 08 May 12 - 04:12 PM This is, I believe, a "copycat" of The Fraside cartoon bt Garry Larrson (spg?). http://www.threadless.com/submission/245734/One_of_these_penguins_IS_NOT_A_PENGUIN/showmore,designs |
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Subject: RE: BS: Math problems From: Mo the caller Date: 08 May 12 - 08:12 AM jonm. I like your lost bear solution. |
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Subject: RE: BS: Math problems From: DMcG Date: 07 May 12 - 05:45 PM Ok, I've completely blown it. That only works for the north and east bit. Once you include the south part, you must end up a mile away. Even so, I reckon moving north for a mile and east for a mile and staying in the bsame place is interesting in its own right! |
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Subject: RE: BS: Math problems From: DMcG Date: 07 May 12 - 05:14 PM (Of course, that's an engineer's definition of ending up in the same place, rather than a mathematicians. But however we handle to going east bit, the somewhat dizzy bear will never be more than one step away from where it started.) |
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Subject: RE: BS: Math problems From: DMcG Date: 07 May 12 - 04:59 PM Well, here's a different solution based on yet another interpretation of what 'go a mile north' could mean. Suppose it were to mean 'take one step in whatever direction is north; then another in whatever direction is north' and do that for say 2000 steps'. Now start one half-step from the north pole. |
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Subject: RE: BS: Math problems From: gnu Date: 07 May 12 - 04:44 PM DMcG... I can't think of any. |
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Subject: RE: BS: Math problems From: DMcG Date: 07 May 12 - 02:16 PM As for that bear, a lot depends on what the phrase 'a mile due north' means. If, for example it means 'face due north and walk a mile in a straight line' there are many more answers than the two given above. |
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Subject: RE: BS: Math problems From: Bert Date: 07 May 12 - 01:27 PM The water wine problem is a logical problem as well as a mathematical one. If you have sets A and B which are of equal sizes and you take a subset of A and join it to set B. Then take a subset the same size as the previous one from set (B plus subset A) and return it to set A then the dilution of each set has got to be the same because the resulting sets are the same size. |
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Subject: RE: BS: Math problems From: DMcG Date: 07 May 12 - 01:13 PM Wrong choice of chemicals, but you get the idea! Pick an acid and an alkaline of your own preference. |
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Subject: RE: BS: Math problems From: DMcG Date: 07 May 12 - 01:09 PM that doesn't work so well because white/black socks will remain intrinsically white/black socks and wine will just get diluted Mudguard has it right, but as for dilution: as I said, think about it at a molecular level. What does it mean to say a single molecule of wine is diluted by one or more of water? Now, if we are talking about the wine and water reacting chemically, that's a different matter. Take litre of H2SO4 and another litre of HCl and move a teaspoonful from one to the other ... that's quite a different experiment! |
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Subject: RE: BS: Math problems From: Jeri Date: 07 May 12 - 09:33 AM I h8 math. :-) |
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Subject: RE: BS: Math problems From: jonm Date: 07 May 12 - 02:58 AM The mile south/east/north and be back where you started has TWO possible locations. The start point is the north pole. The bear is white. The start point is approx. 1 and 1/6 miles from the south pole (so the mile east is an exact circle and the mile north retraces your initial steps. The bear is lost. |
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Subject: RE: BS: Math problems From: MudGuard Date: 07 May 12 - 02:16 AM >> DMcG, that doesn't work so well because white/black socks will remain intrinsically white/black socks and wine will just get diluted. What if you grab a black sock and put it back into the black sock box? You'd have 96 black socks (and 4 white ones) in the black sock box and 95 white socks (5 black ones) in the white sock box. 96 black socks + 5 black socks = 101 black socks. This would mean that one of the previous white socks has turned black. What really happens: after step one, in the white-sock-box you have 100 white socks and 5 black socks, and in the black-sock-box you have 95 black socks. If you happen to pick 4 white + 1 black socks, after step 2 you have: 96 white socks + 4 black socks in the white-sock-box, and 96 black socks and 4 white socks in the black-sock-box. |
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Subject: RE: BS: Math problems From: Jeri Date: 06 May 12 - 11:46 PM DMcG, that doesn't work so well because white/black socks will remain intrinsically white/black socks and wine will just get diluted. What if you grab a black sock and put it back into the black sock box? You'd have 96 black socks (and 4 white ones) in the black sock box and 95 white socks (5 black ones) in the white sock box. We're talking about liquids, not solids. It's more like figuring out PPM (parts per million). It's about concentration or ratio, not numbers. You removed a tablespoon of wine from the liter of wine. You add the tablespoon of unadulterated wine to the water. When you mix the tablespoon of wine into the liter of water, there will be SOME wine in it. You removed a tablespoon of solution from the liter of what once was only water. You add that tablespoon of water and a little wine to the wine. There is less water in the wine than water in the water, because you added a tiny bit of wine back in. You didn't add any water back into the water. Dick Greenhaus, come back here! |
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Subject: RE: BS: Math problems From: Louie Roy Date: 06 May 12 - 10:49 PM The bear was white this can only happen at the North Pole |
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Subject: RE: BS: Math problems From: Mo the caller Date: 06 May 12 - 05:59 PM Isn't it time we met the hunter who went a mile due south, a mile due east, a mile due north and found himself back where he started. What colour was the bear that he shot? |
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Subject: RE: BS: Math problems From: DMcG Date: 06 May 12 - 05:02 AM It's probably easier to see what is happening with the water and wine problem if you think about where each individual molecule is, rather than assuming the liquids are continuous. So to simplify it, do one of the sock experients; Imagine two boxes, one containing one hundred white socks and one containing 100 black socks. Take five from the 'black' box and put them in the white box. Then, eyes closed, mix them all about and without looking take five from the mixed box and put them back in 'black' box. Now, open your eyes! Are there more white socks in the black box or black socks in the white box? Obviously, they must be the same, since every sock is somewhere (unlike in real life!)and there are the same number of socks in each box as there was at the start. |
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Subject: RE: BS: Math problems From: MudGuard Date: 06 May 12 - 03:41 AM Wine and water: if we assume there are no volume effects from mixing, then it is obvious that the amount of water in the wine must be exactly the same as the amount of wine in the water. At the beginning we have two pints (or litres or liters or whatever) of liquid, exactly one half is water, exactly one half is wine. At the end, we have two pints (or ...) of liquid. Still exactly one half is water and exactly the other half is wine. As both containers contain exactly half of the liquid (one tablespoon of liquid was moved from A to B, and then one tablespoon was moved from B to A), whatever amount of water is missing from container A is now in container B. And, as we assumed no volume effects from mixing, exactly the same amount of wine is now in container A. Unless someone has turned water into wine ... |
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Subject: RE: BS: Math problems From: JohnInKansas Date: 06 May 12 - 01:09 AM The water & wine problem must conform to Murphy's axiom: "You can't get anything clean without getting something else dirty," But also to the corollary: "You can get everything dirty without getting anything clean." (It's all in how far you spread the dirt.) John |
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Subject: RE: BS: Math problems From: Jeri Date: 05 May 12 - 10:29 PM There's more wine in the water than water in the wine. What you added to the water was 100% wine. What you added to the wine was one tablespoon from a liter of water with one tablespoon of wine mixed in. What you added to the water was pure wine. What you added to the wine was water and wine. While it's true that one tablespoon of wine was removed from the liter of wine, slightly less than a tablespoon of water was removed from the liter of water--some of it was wine that got put back into the liter of wine. |
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Subject: RE: BS: Math problems From: Nigel Parsons Date: 05 May 12 - 10:10 PM From:dick greenhaus - PM Date: 02 May 12 - 09:08 PM Say you have a liter of water and a liter of wine. You put one tablespoon of wine in the water, mix it, and put one tablespoon of the mixture back into the wine. Is there more water in the wine, or wine in the water? If you start with two one litre (not liter) containers, and after messing about they still each contain one litre of liquid, then any amount transferred from A to B is matched by a similar transfer from B to A. So the total volume of the two containers remains the same. If one container holds 90+xx percent of wine, then the other container contains 90+xx percent of water. |
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Subject: RE: BS: Math problems From: Paul Burke Date: 05 May 12 - 05:21 PM Bollocks of course- "1 pint water + 1 pint water results in not 2 pints of mixture, but about 8% less. " ... should be plus 1 pint alcohol And the wine mix has lost a spoonful, so is now (1-S)(A+SA+SW+SSA) Just solve for the water = (1-S)SW = SW-SSW, The same as A in the other pot. |
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Subject: RE: BS: Math problems From: gnu Date: 05 May 12 - 05:11 PM I'll have a glass of the wine, thanks. |
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Subject: RE: BS: Math problems From: Paul Burke Date: 05 May 12 - 05:08 PM Dick's problem is an odd one, partly because wine is a mixture containing water, and partly because one component of wine- ethanol- dissolves in water such that 1 pint water + 1 pint water results in not 2 pints of mixture, but about 8% less. Although there is "water" at one end of the scale and "wine" at the other, there is no point at which you can say that it has ceased to be water, and become wine- and vice versa. And water is never pure H2O. So one one level, the water is still water and the wine is still wine. But let's simplify- assume no significant change in volume on mixing, and assume that the "wine" is a component that can be labelled put in a pot marked A (for Alcohol). The water is of course marked W, and we assume unit volumes W and A. Let the size of the spoon be S (0 < S < 1). Then a spoon of wine is SA, and putting this in the water results in W+SA. The wine is now (1-S)A. Now take a spoonful of the mixture S(W+SA) = SW + SSA, and add it to (1-S)A = (1-S)A+SW+SSA. The result is A-SA+SW+SSA. The remainder in the water is (1-S)(W+SA) = W-SW+SA-SSA. The quantity of wine in the pot marked W is SA-SSA. The quantity of water in the pot marked A is SW. Therefore there is more (absolute quantity) of water in the wine than there is wine in the water. You might want to go on and work out which is the greater proportion of the other. |
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Subject: RE: BS: Math problems From: Bert Date: 05 May 12 - 05:07 PM Dick, they are the same. Nice one Mudguard, hadn't thought of that. Actually it is the question that is ambiguous 'cos it doesn't specify whether it is a dozen herrings or a dozen 'herring and a half's |
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Subject: RE: BS: Math problems From: MudGuard Date: 05 May 12 - 03:41 PM >> If a herring and a half costs three ha'pence, how much does a dozen cost? about 6 times as much. (because you get a rebate if you buy a full dozen ;-)) |
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Subject: RE: BS: Math problems From: GUEST,josepp Date: 03 May 12 - 12:13 AM /////If C is lying then the number IS 150 but that would mean that A is also lying but only one person is lying. No, the question states " You now have all the information needed to figure out the number EXCEPT one of them is lying. it doesn't actually state that only one of them is lying! (a small point, but badly phrased questions permit multiple correct answers)//// That's funny because there ARE multiple correct answers. I never said there weren't. Therefore, by your statement above, I must have worded it exactly correct. If you disagree, then you must agree that your statement above is shit. Clear on that? |
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Subject: RE: BS: Math problems From: dick greenhaus Date: 02 May 12 - 09:08 PM Say you have a liter of water and a liter of wine. You put one tablespoon of wine in the water, mix it, and put one tablespoon of the mixture back into the wine. Is there more water in the wine, or wine in the water? |
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Subject: RE: BS: Math problems From: gnu Date: 02 May 12 - 02:11 PM How much wood could a woodchuck chuck if a woodchuck could chuck wood? |
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Subject: RE: BS: Math problems From: GUEST,CrazyEddie Date: 02 May 12 - 07:19 AM Nigel, Re: One honest & 99 dishonest. (We may be wrong about the one though!). No, he's honest alright. Unlike the others, if you buy him he STAYS bought. |
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Subject: RE: BS: Math problems From: banjoman Date: 02 May 12 - 06:16 AM I think that the engineer went into the building and asked the person who designed it how tall it was and gave hime the clock as a reward for the information. New problem: If it takes a week to walk a fortnight then how long will it take for a legless spider to crawl out of a pot of jam backwards. Another trick question |
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Subject: RE: BS: Math problems From: BK Lick Date: 02 May 12 - 03:43 AM "79 fish works though" So does 25, 52, and all numbers of the form 27n - 2 where n is any integer. For then: Fisherman 1 leaves 2/3 (27n - 3) = 18n - 2 fish; Fisherman 2 leaves 2/3 (18n - 3) = 12n - 2 fish; Fisherman 3 leaves 2/3 (12n - 3) = 8n - 2 fish. |
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Subject: RE: BS: Math problems From: Nigel Parsons Date: 01 May 12 - 08:00 AM I'm playing catch-up here as I'm on holiday in the Canaries (Isles of dogs, not to be confused with Canary Wharf in London which is on the area previously known as "the isle of dogs"). So: If C is lying then the number IS 150 but that would mean that A is also lying but only one person is lying. No, the question states " You now have all the information needed to figure out the number EXCEPT one of them is lying. it doesn't actually state that only one of them is lying! (a small point, but badly phrased questions permit multiple correct answers!) Bert: Actually, In England we used to call mathematics sums. Strange, in Wales we called Arithmetic 'Sums'. Mathematics (hence the plural 'maths') was the three mathematical disciplines of Arithmetic, Geometry & Algebra. 1 • How much? Suppose you and I have the same amount of money. How much must I give you so that you have ten dollars more than I? 5 dollars 2 • The Politician Puzzle A certain convention numbered one hundred politicians. Each politician was either crooked or honest. We are given the following two facts: (1) At least one of the politicians was honest. (2) Given any two of the politicians, at least one of the two was crooked. Can it be determined from these two facts how many of the politicians were honest and how many were crooked? One honest & 99 dishonest. (We may be wrong about the one though!) 3 • Old Wine in a Not-so-new Bottle A bottle of wine cost ten dollars. The wine was worth nine dollars more than the bottle. How much was the bottle worth? 50cents |
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Subject: RE: BS: Math problems From: Mr Happy Date: 01 May 12 - 07:47 AM .......but what of the hare, did it relope? |
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Subject: RE: BS: Math problems From: Paul Burke Date: 30 Apr 12 - 06:04 PM Let's work that through Doug. 40 fish, throw one away. That's 39. 13 each, so early riser goes off with his share. That leaves 26. Throw one of those away and 25 are left, which doesn't divide evenly by 3. 79 fish works though. Thow one away = 78. Take 26, leaving 52. Next chap throws one away, leaving 51. He takes his 17, leaving 34. Lazybones throws 1 away and takes his 11, leaving 22 to rot. Dirac's answer was much better, though I think he cheated a bit. He proposed that the number of fish caught was -2. Throw one away, that's -3. Take your third, and that leaves -2 again. Any number of fishermen could have shared the catch in this manner. |
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Subject: RE: BS: Math problems From: GUEST,Eliza Date: 30 Apr 12 - 05:31 PM And while we're at it, the plural of formula was formulae! |
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Subject: RE: BS: Math problems From: GUEST,Eliza Date: 30 Apr 12 - 05:30 PM I always thought that the plural of 'antenna' was 'antennae'. |
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Subject: RE: BS: Math problems From: GUEST,CrazyEddie Date: 30 Apr 12 - 04:28 PM That'd be a bob a dozen Bert, but I'll let you have half-a-dozen for a tanner. |
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Subject: RE: BS: Math problems From: Bert Date: 30 Apr 12 - 03:16 PM If a herring and a half costs three ha'pence, how much does a dozen cost? |
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Subject: RE: BS: Math problems From: Newport Boy Date: 30 Apr 12 - 10:51 AM Re the fish problem, where did the first man get the hare from? There proved to be one extra fish. After a moment's thought, he threw it into the water, took his hare, and went home. Phil |
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Subject: RE: BS: Math problems From: Newport Boy Date: 30 Apr 12 - 10:49 AM An old rancher died and stipulated in his will that his horses were to be divided among his 3 sons. His oldest was to get ½ the horses, his 2nd son 1/3, and the youngest son 1/9 of the horses.... but when they checked, there were 17 horses. How did the lawyer solve the problem? The lawyer lent them a horse, so there were 18 horses. The sons received 9 + 6 + 2 = 17 horses, and the lawyer had his horse back. The lawyer charged $100 for the loan of the horse! Phil |
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Subject: RE: BS: Math problems From: Bobert Date: 30 Apr 12 - 10:39 AM ... Mitt Romney - 3... Hey, it was so obvious... B;~) |
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Subject: RE: BS: Math problems From: Bobert Date: 30 Apr 12 - 10:38 AM Child's play, ya'll!!! So I took all the problems and turned them into one of the multi-nomial clusterfuck of problems to be solved as one problem and put it on the Wes Ginny Slide Rule... Well, half an hour later the WGSR had it figured out and the answer was... |
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Subject: RE: BS: Math problems From: Will Fly Date: 30 Apr 12 - 10:08 AM Excel tends to truncate large numbers with the E+ signage - I had to force the full version with commas in the cells formatting - but still not an exact number! |
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Subject: RE: BS: Math problems From: MudGuard Date: 30 Apr 12 - 07:51 AM the exact number of rice grains involved is 18.446.744.073.709.551.615 Excel seems not able to handle such big numbers exactly. |
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Subject: RE: BS: Math problems From: Doug Chadwick Date: 30 Apr 12 - 05:46 AM The sum of all of the grains on the board is 264 - 1 grains In the opening post it says that the man provided the first grain of rice himself, so the king only had to provide 264 - 2 grains. Not as bad as it first seemed then! DC |
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Subject: RE: BS: Math problems From: Will Fly Date: 30 Apr 12 - 05:24 AM Hi John (in Kansas) - just checked the amount of rice using Excel and my forumla - it adds up, as you said, to 18,446,744,073,709,600,000 grains. So, we may differ slightly as to the basis of the calculation, but the result appears to be the same! :-) |
